Gravitational anomoly of a burried magnetite sphere 1. [5 marks] Geophysicists d
ID: 3308852 • Letter: G
Question
Gravitational anomoly of a burried magnetite sphere 1. [5 marks] Geophysicists discover a deposit of magnetite (density of 5000 kg/m°) located in the Earth’s crust (density 2670 kg/m°). Using a gravimeter, they measure the gravitational anomalous cross-section of the deposit (shown to the right) and determines that the profile is consistent with a sphere with a radius to depth ratio of F = 0.5. Determine the depth and the Gravity variation (mgal) . : : : * E E radius of the deposit. 400 100 200 300 distance from vertical, x (m)Explanation / Answer
Geophysicists discover a deposit of magnetite (density of 5000 kg/m3) located in the Earth’s crust (density 2670 kg/m3)
here,
Gmax value is 1.2 mgal at x=0
Then using half widht method, for spherical body,
Half of gmax is 0.6 and distance at this value is about 120 m.
Z=0.652* x1/2.
Z= 78.24 m
Now density variation is (5000-2670) = 2330 kg/m3
Formulae to find radius is
Gmax= ((4/3)r3* density* gravitational constant)/z2
Here, Using this Formula, You can Easily Calculate Radius of the deposit.
----------------------------------------------------------------------------------------------------------------------------------------------------------------------
If you like my answer please give me a thumbs UP! And sorry for any mistake done, please comment about it, I will try my best for providing well explained answers.
Thanks in advance.
BEST REGARDS
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.