Question
Note: Use pinciples of physics to solve the problem and then verity your answer using the simulation. For the questions below assume the block's mation stops when the block reaches x +5 m. Note that in many cases the block goes a litte beyond the 5 m mark, so your answers may be slightly smaller than the numbers frdm the simulation. The numbers from the simulation should be a good check, however (a) Given the limits on the sliders available to you in the simulation, what is the maximum amount of work that can be done on the black if the motion continues until the x +5 m mark? (b) Given the limits on the sliders available to you in the simulation, what is the maximum kinetic energy the block can have if the motion continues until the x +5 m mark? (Hint: Try starting with the highest initial kinetic energy.) (c) Given the limits on the sliders available to you in the simulation, what is the maximum speed the block can have if the motion continues until the x = +5 m mark? (Hint: Try a different mass than was used for part (b)-) mys (d) which of the following situations are possible to achieve with some combination of the slider settings in this simulation? You must select all the possible situations to get credit for this question. The net work done on the block is zero but the block is in a different location than t was when the simulation started. D At some time after the simulation starts the net work done on the block is zero, the block is in the same location as it was when the simulation started but the block has been in motion. The net work done on the block is negative. The net work done on the block is negative and the kinetic energy is larger than the initial kinetic energy Additional Materials
Explanation / Answer
A-
From the slider you can see that the maximum limit for force is 10N.
So maximum work will be when force is maximum.
So work (max) = F×d = 10×5 = 50 J
