2. I have a mass of 60kg. I stand on a bathroom scale in a helicopter. a. While
ID: 3308584 • Letter: 2
Question
2. I have a mass of 60kg. I stand on a bathroom scale in a helicopter. a. While the helicopter is on the ground at rest, what weight will the scale read (in Newtons)? b. While the helicopter accelerates upward at 2m/s2, what weight will the scale read? c. While the helicopter moves upward with a constant velocity of 50m/s, what weight will the scale read? d. While the helicopter accelerates forward in the horizontal direction at 4m/s', what weight will the scale read? In this case, there must be another force present. Why? What magnitude and direction must this force have?Explanation / Answer
A) :as the helicopter is has is standing, so only acceleration due to gravity is acting on mass, and therefore
Weight=mg=60*9.8=588N
B):while the helicopter accelerates upward, a DOWNWARD pseudo force will be applied, which is equal to
Pseudo force =mass x acceleration of helicopter =60*2=120N
And weight due to gravity of earth =mg=60*9.8=588N
So total weight will be =588+120=708N
C):while helicopter moves with constant velocity, means that acceleration of helicopter is zero and the only force acting is due to gravity of earth, so scale reads actual weight i.e 588N there is no extra pseudo force or anything else.
D) :when helicopter accelerates forward, frictional force will be exerted to stabilize body.As the helicopter accelerates in forward direction, it will apply force on body in forward direction and friction will be applied on the body in backward direction, and will be equal to force applied by helicopter i.e 60*4=240N.
As the forces are in horizontal direction, so it has nothing to do with the normal reaction force provided by the scale and thus reading remains same. Reading of scale only changes when there is acceleration in the vertical direction.
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