I am struggling with this portion of the lab. I\'ve spent God knows how many hou
ID: 3308504 • Letter: I
Question
I am struggling with this portion of the lab. I've spent God knows how many hours trying to figure it out and am stuck on this final portion. If anyone can help, I'd be so grateful. If you could write out the the answer clearly, that would be nice. Thank you in advance.
Fill out the last column of the table.
After the last column has been filled, the question is: do the standard values of resitivity (I provided the resistivity values in each respective row) fit within their corresponding uncertainty brackets calculated in the table? If any do not, please hypothesize why.
**** PLEASE NOTE****: For some reason it won't let me add a big enough table to provide the last column in the table above so here is the last column heading for the above table:
U() U' D(cm) Area() Coil 1 (copper: 0.934 104 52.5 .0644 .00326 Coil 2 (copper: 3.360 28.8 16.1 0.0321 0.00081 Coil 3 (copper: 1.793 55.8 28.8 0.0644 0.00326 Coil 4 (copper: 7.020 14.20 10.60 0.0321 0.00081 Coil 5 (silver-copper: 14.2 7.05 10.6 0.0644 0.00326 p= UavgExplanation / Answer
Resistance is the mesure of the difficulty to pass an electrical current and it is inversly proportional to the conductance of the material. The following realtion we know,
Resistace = Resistivity*(length/area)
Resistivity = Resistance*(area/length)
The data provided in the table does not contain length of the wire from which these readings were taken and that is why the whole ambibuitiy is here. The D(cm) values given in the table is daimeter of the cross section not the length that is why you are getting error in the resistivity calculation.
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