I am having problems with finding Mb EXPERIMENT 5 Title: Deduction from graphs A

Question

I am having problems with finding Mb

EXPERIMENT 5 Title: Deduction from graphs Aim: Determination of the mass of a beaker and the density of the liquid in the beaker and to find a relationship between total mass of the beaker-liquid combination and depth of liquid Apparatus Balance . Liquid . 2 beakers . Vernier callipers Theory & Discussion The mass of the liquid and beaker are Mi and Mb respectively The total mass MT is the sum of the mass of the liquid and the mass of the beaker (eqn. 1) The mass of the liquid MI = density of the liquid x volume of liquid, ie. M If the cross-section area of the liquid in the beaker is A and the depth of the liquid in the beaker is h, then we can write TASK Show how the above information can be used to arrive at the following equation Mr = (pA)h + (eqn.2) Procedure Place about 30 ml of the liquid in the beaker. Measure MT on the triple beam balance and use a vernier calliper to determine the depth (h) of the liquid. Increase the depth of the liquid and measure values of MT and the corresponding values of h, until 12 sets of data are contained Graph: Plot an appropriate graph of MT vs h Evaluation/Calculation: 23 a) Use the graph to determine the mass Mb of the beaker H. Simpson/Deduction From Graphs) b) Use the calliper to determine the average diameter of the beaker, hence with the aid of the graph determine the density of the liquid c) With your constants determined, write down the specific straight line equation which represents the relationship between MT and h. Submit a short report of your findings at the end of the laboratory period Remember, your report should contain

Explanation / Answer

given
mas of liquid = Ml
mass of beaker = Mb
total mass Mt = Ml + Mb
density of liquid = rhol
Volume of beaker = Vl

hence
Ml = rhol*Vl
Mt = Ml + Mb = rhol*Vl + Mb

now if area of cross seciton of the beaker is A
depth of iquid = h
then Vl = h*A
hence
Mt = rhol*h*A + Mb

now, when we plot Mt vs h, we get an equaion of the form
y = mx + c
here m = slope of the curve = rho*A
c = mass of the beaker = Mb

hence the intercept of the line of the y axis gives us the mass of the beaker Mb

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.