ldMapping (thus 3. How much work is required to turn an electric dipole 180° in
ID: 3308153 • Letter: L
Question
ldMapping (thus 3. How much work is required to turn an electric dipole 180° in a uni magnitude 43.9 N/C if p 3.53 x 1025 C-m and the initial angle is 38.4 iform electric field of much work is required to turn an electric dipole 180° in a uniform electric field of magnitude 30.1 N/C if p 1.99 x 1025 C-m and the initial angle is 69.9. 5. A certain electric dipole is placed in a uniform electric field of magnitude 73 N/C. The figure gives the magnitude of the torque on the dipole versus the angle between field and the dipole moment. The vertical axis scale is set by t, 134 x 102 N-m. What is the magnitude of the dipole momentExplanation / Answer
3. PE = - p E cos(theta)
Work done = - p E (cos218.4 - cos38.4)
= 1.567 pE
= 1.567 x 3.53 x 10^-25 x 43.9
= 2.43 x 10^-23 J
4. PE = - p E cos(theta)
Work done = - p E (cos(180 + 69.9) - cos69.9)
= 0.687 pE
= 0.687 x 1.99 x 10^-25 x 30.1
= 4.12 x 10^-24 J
5. torque = p E sin(theta)
134 x 10^-28 = p x 73
p = 1.84 x 10^-28 C m
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