For 79 c why is v(0) equal to 2kq/a? Charge is supplied to the metal dome of a V

Question

For 79 c why is v(0) equal to 2kq/a? Charge is supplied to the metal dome of a Van de Graaff ners of a square generator by the belt at the rate oi aupys when the potential difference between the belt and the dome is 1.25 MV. The dome transfers charge to the atmosphere at the same rate, so the 125 MV potential difference is maintained. What minimum power is needed to drive the moving belt and maintain the 1.25 MV potential difference? f the square is 2a. (-a, -a). A fifth placed at the ori- en it is a very far ve charge +e, are A positive point charge +Q is located on the x axis at How much workx--a. (a) How much work is required to bring an identical point y large separation inetic energy willthe two identical point charges in place at x -aand +a, how heir separation at (1.00 amu m each other? charge from infinity to the point on the r axis at r +a? (b) With much work is required to bring a third point charge -Q from in- charge-Q from the origin to the point on the x axis at x -2a along ). Whatfinity to the origin? (c) How much work is required to move the the semicircular path shown (Figure 23-35)? t are initially at rest motion of the much kinetic energy and cted at so it reaches ? Assume the elec-a -Q 0 2a proton. (c) How n if it has twice that the FIGURE 23-35 Problem 79 o 4.80×10-29C is same magnitude otential at a pointo 8o A charge of +2.00 nC is uniformly distributed on a ring of radius 10.0 cm that lies in the x 0 plane and is centered at the origin. A point charge of +100 n is initially located on the x axis ave a charge of t a nd he elat y500 cm Find the work required to move the point charge to ) Use your result in the origin. ITne motal spheres each have a radius of 100 cm. The

Explanation / Answer

Potential at origin will be due to two charges placed at x = -a and x= +a

Both charges are positive so potential due to both will also be positive.

V1 = kQ/a

V2 = kQ/a

So net potential = V1 + V2 = kQ/a + kQ/a = 2kQ/a

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