I also answered 3.977e6 for part b and said it was wrong... what am I missing? W
ID: 3307971 • Letter: I
Question
I also answered 3.977e6 for part b and said it was wrong... what am I missing?
WL A particle with charge of 35.2 uC is placed at the center of a spherical shell of radius 21.5 cm. (a) What is the total electric flux through the surface of the shell? 3.977e6 N m2/c b) What is the total electric flux through any hemispherical surface of the shell? what is the flux through the flat bottom of the hemisphere? N·m2/C (c) Do the results depend on the radius? O Yes (e) No Explain your answer The total electric flux is not dependent on the radius because of Gauss's law, The net flux is independent of the shape of the surface and it is proportionate to the net charge enclosed by that surface. Score: 1 out of 1 Comment:Explanation / Answer
a-
Total electric flux through the shell surface will be
Flux = Q/e0 = 35.2 ×10^-6 / 8.854×10^-12 = 3.976e^6 N.m^2/C
b-
Electric flux through any hemispherical surface of the shell will be half of above value.
Flux = 3.976e^6/2 =1.988e^6 N.m^2/C
C-
Results don't depend on radius. It only depends on charge and surface area.
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