capacitors in parallel, series, charging, discharging Questions: If you had a ci
ID: 3307632 • Letter: C
Question
capacitors in parallel, series, charging, discharging
Questions: If you had a circuit with a capacitor and resistor, how could you make the charging/discharging time shorter by adding a resistor? If you had a circuit with a capacitor and resistor, how could you make the charging/discharging time longer by adding a resistor? The voltage meter has some resistance and as such will always allow some current to flow. How would it affect your data if the resistance used in the circuit were near to the resistance in the voltmeter (i.e. voltage sesor)? If you had a current sensor (ammeter) instead of a voltmeter, how could we get the same data without using a voltmeter? Be specific! Do you think it would be easier or more complicated? Would it be more or less accurate? Draw a circuit that uses the ammeter with the location of the ammeter shown.Explanation / Answer
1)We know that the time constant of a capacitive circuit with resistance R is given by:
Tau = RC
for reducing the time constant, we need to decrease the value of resistance.
We can do this by adding a resistor parallel to the existing one and the overall resistance of the circuit will be reduced and so will be the time constant.
2)We know that the time constant of a capacitive circuit with resistance R is given by:
Tau = RC
for making the time constant longer, we need to increase the value of resistance.
We can do this by adding a resistor in series to the existing one and the overall resistance of the circuit will be increased and the time constant will also be increased.
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