se you just received a shipment of twelve televisions. Four of the televisions a
ID: 3307336 • Letter: S
Question
se you just received a shipment of twelve televisions. Four of the televisions are defective. If two televisions are randomly seledted, compute the probability that both televisions work What is the probability at least one of the two televisions does not work? The probability that both televisions work is ound to three deimal places as needed) The probability that at least one of the two televisions does not work is Round to three decimal places as needed) Enter your answer in each of the answer boxes javascript:doExercise(12) 2 4 5 6 7Explanation / Answer
There are two outcomes-success (television is non defective) and failure (television is defective). The probability of success, p=8/12. There are n=2 random independent trials and probability of success is constant throughout the trials. This accounts for binomial distribution. Use, Binom(2,8/12) to compute the required probability. Assume X denote the number of televisions that works.
P(X=2)=2C2(8/12)^2(1-8/12)^0 [P(X,r)=nCr(p)^r(1-p)^n-r, where, p is the probability of success, r is the specific number of successes in n trials]
=0.449
Assume Y denote number of televisions that doesnot work.
P(Y>=1)=1-P(Y<1)=1-P(Y=0) [Note, n=2, r=0, p=4/12, as probability of success here, refer to probability of a television that does not work]
=0.551
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