The district manager of Jasons, a large discount electronics chain, is investiga
ID: 3307068 • Letter: T
Question
The district manager of Jasons, a large discount electronics chain, is investigating why certain stores in her region are performing better than others. She believes that three factors are related to total sales: the number of competitors in the region, the population in the surrounding area, and the amount spent on advertising. From her district, consisting of several hundred stores, she selects a random sample of 30 stores. For each store she gathered the following information.
What are the estimated sales for the Bryne store, which has four competitors, a regional population of 0.4, and advertising expense of 30? (Omit the "$" sign in your response.)
Compute the multiple standard error of estimate. (Round your answer to 3 decimal places.)
State the decision rule. H0: 1 = 2 = 3 = 0; H1: Not all 's are 0. Use the .05 level of significance. (Round your answer to 2 decimal places.)
State the decision rule. Use the .05 significance level. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.)
The district manager of Jasons, a large discount electronics chain, is investigating why certain stores in her region are performing better than others. She believes that three factors are related to total sales: the number of competitors in the region, the population in the surrounding area, and the amount spent on advertising. From her district, consisting of several hundred stores, she selects a random sample of 30 stores. For each store she gathered the following information.
Explanation / Answer
a. What are the estimated sales for the Bryne store, which has four competitors, a regional population of 0.4, and advertising expense of 30?
Answer : Y = 14.00 - X1 + 30 X2 + 0.20 X3
X1 = Number of competitiors = 4
X2 = Population in regions = 0.4 million
X3 = advertising expense = 30 thousand dollars
Y^= 14.00 - 4 + 30 * 0.4 + 0.20 * 30 = 28 thousand dollar
(b) Coefficient of determination R2 = 3050/ 5250 = 0.581
(c) multiple standard error of estimate = sqrt(SSresidual /dF) = sqrt (2200/ 26) = 9.1987
(d) State the decision rule. H0: 1 = 2 = 3 = 0; H1: Not all 's are 0. Use the .05 level of significance.
H0 is rejected if F > 3.49 [ Fcr for dF1 = 3, dF2 =26]
Computed F = 1016.67/ 84.62 = 12.0145
We shall reject the null hypothesis. F > Fcr At least one regression coefficient is not zero.
E(1) For dF = 26 , critical value tcr = 2.0555
so for variable x1 , l t l < tcr so we say that it cannot reject the nul hypothesis.
so for variable x2 , t > tcr so we can reject the null hypothesis.
For variable x3 ,t > tcr so we can reject the null hypothesis.
(b) so we can drop the variable X1 number of competitors in the region
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