I dont think my answers are correct The DataView tool that follows displays a da
ID: 3306672 • Letter: I
Question
I dont think my answers are correct
The DataView tool that follows displays a data set consisting of 200 potential samples (each sample has 64 observations) Data Set Sample Variables 2 Observations 200 Samples Samples SampleSample Means Sample SD 0.1130 0.1030 0.1050 0.1020 0.1200 0.1200 0.0990 0.1070 0.1000 0.1060 0.1350 0.1180 0.1050 0.1040 0.1110 83 84 85 86 87 0.803 0.796 0.808 0.810 0.773 0.775 0.782 0.786 0.751 0.816 0.780 0.792 0.819 0.782 0.790 Variables > 89 90 92 93 94 95 96 97 Variable Variable Correlation Correlation Suppose this professor happens to select Sample 83. (Hint: To see a particular sample, click the Observations button on the left-hand side of the DataView tool. The samples are numbered in the first column, and you can use the scroll bar on the right side to scroll to the sample you want.) Use the DataView tool to find the mean and the standard deviation for Sample 83. The mean for Sample 83 is 0.803 . The standard deviation for Sample 83 is 0.1130 . Using the distribution of sample means, calculate the z-score corresponding to the mean of Sample 83. The z-score corresponding to the mean of Sample 83 is 0.73 Use the Distributions tool that follows to determine the probability of obtaining a mean percent accuracy greater than the mean of Sample 83Explanation / Answer
your answer seems to be correct.
you calculate z score using software and yes you have to select both tailed probabilities.
The worst sample you can select, as hint given short sample mean, take that sample mean which is far deviated from the population mean.
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