please I would really appreciate any help on this problem. It has already been s

Question

please I would really appreciate any help on this problem. It has already been solved on this website, but turns out that a); c) and e) are not correct. Thank you!

(1 point) You are to pick 4 cards randomly from a condensed deck of cards that contains four suits -9,0ands the fallowing denomations: Ace, 2, 3, 4, 5, 6, 7, 8,9, and 10. There are no face-cards in this deck. What is the probability that you will get Part (a) a three-of-a-kind? P(3 of a kind) 0158 Part (b) What is the probability that all four cards are of the same suite? For example, all four cards are 9s? i (use four decimals) P(all the same suit) = 0092 Part (c) What is the probability you get one-pair? P(one pair)0355 Part (d) What is the probability you get two aces and two 10s? P(2 - aces and 2- 10s)0004 Part (e) What is the probability you get two aces and two Vs? P(2-aces and 2-C) 0.0024 (use four decimals) (use four decimals) (use four decimals) (use four decimals)

Explanation / Answer

(A)

Probability of getting three of a kind = (4*10C3)/(40C3) = 0.0486

(C)

Probability of getting 2 aces and 2 hearts = ( (4/40)*(3/39)*(10/38)*(9/37) ) + ( (4/40)*(3/39)*(9/38)*(8/37) ) = 0.0008

Hope this helps !

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