This data is obtained from witchtrials.dta (Stata). 1.) Use the regression out p

Question

This data is obtained from witchtrials.dta (Stata).

1.) Use the regression out put to test the hypothesis that the mean of trialindex is the same for location/decades with cold=1 as it is for location/decades with cold = 0, against the alternative that they differ at the 5% significance level.

. reg trialindex cold, r Number of obs F(, 168) Prob > F R-squared Root MSE 170 4.74 0.0309 0.0275 96106 Linear regression Robust Std. Err. trialindex Coef. t P>|t| [95% Conf. Interval] 0299335 3501699 6130207 0440272 cold . 3214771 .1530713 147678 0998379 2.18 0.031 -1.53 0.127 cons

Explanation / Answer

here null hypothesis H0:mean(cold=1)=mean(cold=0)

and alternate hypothesis H1: mean(cold=1) is not =mean(cold=0)

we use t-test and t=coeff(cold)/SE(cold)=0.3215/0.1477=2.18 and its p-value=0.03 is less than alpha=0.05

so we reject H0 and conclude that mean of trialindex is not the same for location/decades with cold=1 as it is for location/decades with cold = 0, at the 5% significance level.

for cold=1, mean of trialindex=-0.1531+1*0.3215=0.1684

for cold=0, mean of trialindex=-0.1531+0*0.3215=-0.1532

difference of means=0.1684-(-0.1532)=0.3216

we use t-test and t=

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