Suppose city police and paramedics know that the 95% confidence interval on the

Question

Suppose city police and paramedics know that the 95% confidence interval on the proportion of calls for drug overdoses that end in fatalities is (0.775, 0.792).

What must be the value of p , the point estimate for the proportion of calls for drug overdoses that end in fatalities?

What is the critical score that would be used to calculate the 95% confidence interval?

When can you use a T-score to calculate a confidence interval for a proportion?

Use the information you have for the two-sided 95% confidence interval to determine the level of confidence you would have if you were told that 0.775 is the one-sided lower bound for the confidence interval on the proportion of calls for drug overdoses that end in fatalities?

Thanks!

Explanation / Answer

1) point estimate for the proportion =(0.775+0.792)/2=0.7835

2) critical score that would be used to calculate the 95% confidence interval z =1.96

3) when sample size is less then 30

if 0.775 is one sided  lower bound then we should use 97.5%  confidence interval or 0.025 level of confidence

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