2. Left-handed People: The table below shows the results of a survey of 1000 peo

Question

2. Left-handed People: The table below shows the results of a survey of 1000 people. The table is bivariate. Gender and dominant hand are the two variables surveyed. A person is selected at random from the sample. Find the probability of each event. GENDER Dominant Hand Left Right Tota Men 63 462 525 Women 50 425 475 Tota 113 887 1000 a. The person is left-handed b. The person is left-handed or a man c. The person is a right-handed woman. d. The person is left-handed, given that the person is a man e. The person is a woman, given that the person is right-handed

Explanation / Answer

2. a) P(person is left handed) = 113/1000 = 0.113

b) P(left handed or a man) = (63+462+50)/1000 = 0.575

c) P(right handed woman) = 425/1000 = 0.425

d) P(left handed | man) = P(left handed and man) / P(man)

= 63/525

= 0.12

e) P(woman | right handed) = P(right handed and woman) / P(right handed)

= 425/887

= 0.4791

P.S - Please post different questions separately

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