Statistical quality control question C5. Consider a control chart design using 3

Question

Statistical quality control question

C5. Consider a control chart design using 3 sigma control limits, n-10, and h- 20 minutes, which the statements are true? (Multiple answers may be possible.) ARL-average run length and ATS-average time to signal. If you are not sure about your answers, please list your formulations in the questions. Refer it as C5 When there is a 1.5 sigma shift, ATS-21 minutes When the process is in control, ATS is 123 hours. When there is a 1.5 sigma shift, ARL-1.05 When the process is in control, ATS is 370 hours

Explanation / Answer

ARL = 1/p = 1/0.0027 = 370   p is 0.0027 under 3 sigma limit.

ATS = ARL*h = 370*1/3 hours = 123 hours            {20 min = 1/3 hours}

option B) is correct

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