The Downtown Parking Authority of Tampa, Florida, reported the following informa
ID: 3304834 • Letter: T
Question
The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 228 customers on the number of hours cars are parked and the amount they are charged.
1. Convert the information on the number of hours parked to a probability distribution
2. Find the mean and the standard deviation of the number of hours parked. (Do not round the intermediate calculations. Round your final answers to 3 decimal places.)
3. How long is a typical customer parked? (Do not round the intermediate calculations. Round your final answer to 3 decimal places.)
4. Find the mean and the standard deviation of the amount charged. (Do not round the intermediate calculations. Round your final answers to 3 decimal places.)
1. Convert the information on the number of hours parked to a probability distribution
2. Find the mean and the standard deviation of the number of hours parked. (Do not round the intermediate calculations. Round your final answers to 3 decimal places.)
3. How long is a typical customer parked? (Do not round the intermediate calculations. Round your final answer to 3 decimal places.)
4. Find the mean and the standard deviation of the amount charged. (Do not round the intermediate calculations. Round your final answers to 3 decimal places.)
228Explanation / Answer
below is the probability distribution for number of hours:
2) mean =4.14
std deviation =2.161
3) a typical customer parked for 4 hours ( beinig of highest frequency)
4) for amount charged below is frequency distribution:
mean =12
std deviaiton =5.7113
x frequency p(x) xP(x) x2P(X) (x-)2 (x-)2P(x) 1 18 0.0789 0.079 0.079 9.834 0.776 2 38 0.1667 0.333 0.667 4.562 0.760 3 50 0.2193 0.658 1.974 1.290 0.283 4 45 0.1974 0.789 3.158 0.018 0.004 5 20 0.0877 0.439 2.193 0.747 0.065 6 16 0.0702 0.421 2.526 3.475 0.244 7 5 0.0219 0.154 1.075 8.203 0.180 8 36 0.1579 1.263 10.105 14.931 2.357 total 228 1 = 4.14 21.776 43.060 2= 4.6701 std deviation= = 2 = 2.1610Related Questions
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