1. A research facility has a position open. The probability that an applicant ha
ID: 3304589 • Letter: 1
Question
1. A research facility has a position open. The probability that an applicant has had lab safety training is 0.68. The probability tht an applicant has had hazardous material training is 0.66. The probability that an applicant has had both safety training and hazardous material training is 0.35. a. What is the probability that an applicant has had either safety training or hazardous material training? ANS: What is the probability that a randomly selected person has had safety training given they have already had hazardous material training? b. ANS: safety training and hazardous material training mutually exclusive? Why or why not?Explanation / Answer
Probability that an applicant has had lab safety training, P(S) = 0.68
Probability that an applicant has had hazardous material training, P(H) = 0.66
Probability that an applicant has had both the trainings, P(S and H) = 0.35
(a)
Required probability, P(P U S) = P(S) + P(H) - P(S and H) = 0.68 + 0.66 - 0.35 = 0.99
b)
Required probability, P(S|H) = P(S and H) / P(H) = 0.35/0.66 = 0.5303
c)
Safety training and hazardous material training are not mutually exclusive as P(S and H) is not equal zero
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