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C www.webassign.net/web/StudentAssignment-Responses/submit?dep=16928998 7. 014 points I Previous Answers DevoreStat9 1.E.061 My Notes Ask Your An article reported the following data on oxidation-induction time (min) for various commercial oils 87 104 130 160 180 195 135 145 213 105 145 153 154 138 87 99 92 119 129 (a) Calculate the sample variance and standard deviation. (Round your answers to three decimal places.) s2= 33766.18 min2 s= 183.75 X min (b) the observations were reexpressed in hours, what would be the resulting values of the sample variance and sample standard deviation? Answer without actually performing the reexpression. (Round your answer to three decimal places.) s2= 9.38 s= 3.06 hr 8. 1/1 points | Previous Answers DevoreStat9 1.E.05B. My Notes Ask Your Te A company utilizes two different machines to manufacture parts of a certain type. During a single shift, a sample of n = 20 parts produced by each machine is obtained, and the value of a particular critical dimension for each part is determined. The comparative boxplot below is constructed from the resulting data. MachineExplanation / Answer
(a) Oxidation Induction time in min
mean = xbar = 135.2632
Sample variance = 23157.6842 / (n-1) = 23157.6842 / 18 = 1286.5308 min2
Sample std. dev. = sqrt(1286.5308) = 35.8683 min
(b)
Converting given data into hours by dividing 60
sample variance = 6.4327 / 18 = 0.3574 hr2
sample std. dev. = sqrt(0.3574) = 0.5978 hr
xi (xi-xbar)^2 87 2329.33241 104 977.3850416 130 27.70083102 160 611.9113573 180 2001.385042 195 3568.490305 135 0.069252078 145 94.80609418 213 6043.01662 105 915.8587258 145 94.80609418 153 314.5955679 154 351.0692521 138 7.490304709 87 2329.33241 99 1315.01662 92 1871.700831 119 264.4903047 129 39.22714681 23157.68421Related Questions
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