Drosophila melanogaster , the fruit fly, is routinely used in genetic studies. A

Question

Drosophila melanogaster, the fruit fly, is routinely used in genetic studies. A cross between the wild-type (red eye) and mutant-type (white eye) produced the following results:

A. State the null hypothesis.

B. State the alternative hypothesis.

C. Fill in the table and show work below.

D. What is the chi-square statistic?

E. Determine the degrees of freedom.

F. Use the Chi-Square Table to determine the probability.

G. Did you accept or fail to reject your null hypothesis at a=5%? Provide brief explaination.

**Chi-Square Table**

Observed Expected (O-E) (O-E)2 (O-E)2/E Wild-type 68 Mutant-type 32 Totals 100 Upper Tail Areas (a) Degrees of Freedom 995.99 975 95 025 0 0.00 0.00 0.016 0102 1323 2.706 3841 5.024 6.635 7879 0.010 0.020 0.05 0.103 0.21 0575 2.773 605 5.991 7.378 9.210 10597 0,072 0,115 0,216 0.352 0.584 1213 4.108 6.25 7,815 9.348 11.345 12.838 0,207 0,297 0.484 0.7 106 1923 5.385 7.779 9488 11.143 13.277 14.860 0.412 0.554 0.831 .145 1610 2675 6.626 9.236 11.071 12833 15.086 16.750 0.676 0.872 1.23 1635 2.2 3455 7.8 10645 12.592 14.449 16.812 18.548 0.989 1.239 1.690 2.167 2.833 4255 9,037 12.017 14.067 16,013 18.475 20,278 1.344 1.646 2.180 2.733 3.490 507 10.219 13.362 15.507 17.535 20090 21.955 1.735 2.088 2.700 3.325 .168 5899 11.389 4.684 16.919 19.023 21.666 23.589 2.156 2.558 3,247 3940 4.865 6737 2.549 15987 18.307 20483 23.209 25.188 2.603 3.053 3.816 4.575 5.578 7584 13.701 17.275 19675 21.920 24.725 26.757 3.074 3.57 4.404 5.226 6.304 8438 14.845 18.549 21026 23.337 26.217 28.299 3,565 4.107 5.009 5892 7042 999 15.984 19,812 22.362 24.736 27.688 29.819 4.075 4.660 5,629 6.57 7.790 10.165 17.117 21064 23.685 26119 2914 31.319 4.601 5.229 6.262 7.261 8.547 11037 18.245 22.307 24.996 27.488 30.578 32.801 5.142 5,812 6,908 7962 9.312 11912 19.369 23.542 26,296 28845 32.000 34.267 5,697 6.408 7.56 8,672 10.085 12.792 20.489 24.769 27587 30191 33.409 35.718 6.265 7.015 8.23 9.390 10.865 13675 21.605 25.989 28.869 31.526 34.805 37.156 6.844 7.633 8.907 0,117 11651 14562 22.718 27.204 30.144 32.852 36.191 38.582 7.434 8.260 9.591 10,851 12.443 15452 23,828 28,412 31.410 34.170 37.566 39.997 8.034 8.897 10.283 11591 13.240 16344 24.935 29.615 32671 35.479 38.932 1.401 8.643 9.542 10.982 12.338 14.042 1740 26.039 30.813 33.924 36.781 40.289 42.796 9,260 10.196 11689 13091 14.848 18.137 27.41 32.007 35.172 38.076 41638 44.181 9.886 10,856 12.40 13.848 15.659 19.037 28,241 33.196 36415 39.364 42.980 45.559 0.520 11.524 13.120 14.611 16.473 19.939 29.339 34.382 37652 40646 44.314 46.928 11.160 12.198 13.844 13.379 17.292 20843 50.435 33.363 58.885 41923 45.642 48.290 11.808 12.879 14.573 16,15 18.1 21749 31.528 36.74 40,113 43.194 46963 49645 12.461 13.565 15.308 16.928 18939 22657 32.620 37.916 41.337 44.461 48 278 50 993 13.121 14.257 6,047 17.708 19.768 23567 33,711 39.087 42.557 45.722 49.588 52.336 13.787 14.954 16.791 18.493 20.599 24478 34.800 40.256 43.773 46.979 50892 53.672

Explanation / Answer

A. State the null hypothesis.

Null - wild-type (red eye) and mutant-type have same distribution

B. State the alternative hypothesis.

wild-type (red eye) and mutant-type have different distribution

C. Fill in the table and show work below.

D. What is the chi-square statistic?

TS = 12.96

E. Determine the degrees of freedom.

df= r-1 = 1

F. Use the Chi-Square Table to determine the probability.

critical value = 3.841

G. Did you accept or fail to reject your null hypothesis at a=5%? Provide brief explaination.

since TS > critical value {12.96 > 3.841}

we reject the null hypothesis

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