A geologist is exploring the relationship between iron ore concentration and the
ID: 3297956 • Letter: A
Question
A geologist is exploring the relationship between iron ore concentration and the depth of the ore beneath the surface. Sixteen locations were randomly selected at a survey site, and an ore sample was taken at each location. At four randomly selected locations samples were taken at a depth of 1,000 metres, another four randomly selected locations were drilled to 600 metres, and samples at the remaining eight locations were taken at a depth of 400 metres. The sixteen ore samples were then analysed for their concentration of iron ore. The results are available as given below.
a. It is commonly believed that the true mean iron ore concentration found at 600 metres is given by a weighted average of the true mean iron ore concentrations found at 400 metres and 1,000 metres. In particular, the weight of each of the individual means is determined by how far the drilling depth is from 600 metres. The closer to 600 metres the drilling depth is, the greater the weight corresponding to that particular mean.
(i) Give a reasonable set of hypotheses to test this theory.
(ii) Carry out a test of these hypotheses.
b. (i) What is the relationship between ore concentration and depth?
(ii) Between this model and the model considered in (a) above, which is the better model?
(iii) Provide an estimate for the ore concentration at 1,200 metres. Why might this estimate not be appropriate?
(iv) Provide a reasonable range of values that you might expect to contain the ore concentration for a random sample at 800 metres.
OreConcentration Depth 0.354 400 0.28 400 0.745 400 0.387 400 0.413 400 0.261 400 0.508 400 0.643 400 0.574 600 0.745 600 0.367 600 0.45 600 0.689 1000 0.789 1000 0.926 1000 0.647 1000
Explanation / Answer
b) Solution.
Kruskal-Wallis Test: Ore Concentration versus Depth
Kruskal-Wallis Test on Ore Concentration
Depth N Median Ave Rank Z
400 8 0.4000 6.1 -2.05
600 4 0.5120 8.4 -0.06
1000 4 0.7390 13.5 2.43
Overall 16 8.5
H = 6.51 DF = 2 P = 0.039
H = 6.52 DF = 2 P = 0.038 (adjusted for ties)
* NOTE * One or more small samples
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