A mechanic sells a band of automobile tire that has a life expectancy that is no

Question

A mechanic sells a band of automobile tire that has a life expectancy that is normally distributed, with a mean life of 28,000 miles and a standard deviation of 2600 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires? Click to view page 1 of the table. Click to view page 2 of the table. Tires that wear out by miles will be replaced tree of charge. (Round to the nearest mile as needed.)

Explanation / Answer

We will find 90% Percentile

90% Percentile = 1.2815*2600+28000 =31332

So, answer is 31332

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