Marquette examined time pressure and performance. She measured the number of the
ID: 3296978 • Letter: M
Question
Marquette examined time pressure and performance.
She measured the number of the times
participants correctly completed a riddle during a
timed-test. When the study was completed, the
following data were reported:
n = 1400 Mean = 5.341 min.
S2 = 2.849 min S = 1.688 min.
a
The values of the variance and standard deviation are reversed.
b
Either the reported value of the variance or the value of the standard deviation is wrong.
c
There are no obvious errors.
d
The variance could never be this number.
2.) In a recent study, married women were asked
to indicate how happy they were with their marriage
on a scale of 1 (not happy) to 5 (very happy).
The researcher reported the following results:
n = 24 Mean = 3.27
S2 = -.548
a
Either the reported value of the variance or the value of the standard deviation is wrong.
b
There are no obvious errors.
c
The values of the variance and standard deviation are reversed.
d
The variance could never be this number.
3.)
Before passing back the graded quiz to
students, the professor wrote the following quiz
statistics on the board:
n = 44 Mean = 62.333 points
S2 = 11.00 points S = 121 points
a
There are no obvious errors.
b
Either the reported value of the variance or the value of the standard deviation is wrong.
c
The variance could never be this number.
d
The values of the variance and standard deviation are reversed.
4.) Dr. Crane carried out a memory study and reported
the following data on the age of the participants:
n = 45 | Mean = 23 | S2 = 169 | S = 12
a
The values of the variance and standard deviation are reversed.
b
The variance could never be this number.
c
There are no obvious errors.
d
Either the reported value of the variance or the value of the standard deviation is wrong.
a
The values of the variance and standard deviation are reversed.
b
Either the reported value of the variance or the value of the standard deviation is wrong.
Explanation / Answer
1) The value of variance is squared value of standard deviation here. So it is correct. Also the mean looks feasible. So the correct choice is Option(c) there are no obvious errors. (Ans).
2) The variance can never be negative. So it can't be this number. So Option (d) is the correct choice. (Ans).
3) Here the values of variance and standard deviation is reversed. So Option (d) is the correct choice. (Ans).
4) Here variance is not the squared value of standard deviation. So either the reported value of variance or standard deviation is wrong. Hence, Option (d) is the correct choice. (Ans).
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