The university wants to promote the graduates of its honors program by proving t
ID: 3295424 • Letter: T
Question
Explanation / Answer
Answers to the question, below:
a.
The hypothesis can set up as:
Ho:Mu<=3.5
Ha:Mu>3.5
b. the critical value at 5% significance level is Z = 1.645
c. test statistic = Z
= (X-Mu)/(Sigma/sqrt(n))
= (3.6-3.5)/(.4/sqrt(36))
= 1.5
Decision: Since test statistics is lesser than critical value of 1.645 it lies in the non critical range, thus we do not reject Ho. We conclude that it doesn't exceed 3.5
d. p-value at Z = 1.5 is 1-.9332 = .0668. Again alpha = .05<.0668 so our point lies outside the critical region and we do not reject Ho. We conclude that it doesn't exceed 3.5
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.