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@Take . Sninum . Geogle Cheerne INSS 220(Analytical Decision-Making for BUS and

ID: 3295317 • Letter: #

Question

@Take . Sninum . Geogle Cheerne INSS 220(Analytical Decision-Making for BUS and MGMT) SUMMER 20 Quiz: Module 4 Quiz - Chapter 8 This Question: 12 pts 70, 7 (5 complete) This Construct a MN cortdence mervattoestimate the poputason mean when ajn- 40 b)n7Oe) 100 137 and s·34for me sanee sizes below a, The 96% conhdence merval for the populaton mean when n·40istomatower wme ortoanupper nitof Round to two decimal places as needed) D)The 96% cont ence nterval for me popolnon mean when n " 70stom a lower limtoftoan upper Intofi Round to teo decimal places as needed eine 9e% contoence nterval tr ne popinaton mean whenn-100 s tom a over int oDtoanteper int or Round to two decimal piaces as needed) o e

Explanation / Answer

since here sample standard deviation s is given , so we use t-distribution to find confidence interval

sample mean=137 and s=34

(1-alpha)*100% confidence interval for population mean=sample mean±t(alpha/2,n-1)*s/sqrt(n)

90% confidence interval for population mean=137±t(0.1/2, n-1)*34/sqrt(n)

(a) for n=40, confidence interval=137±t(0.1/2, 39)*34/sqrt(40)=137±1.685*34/sqrt(40)=137±9.06=(127.94,146.06)

lower limit=127.94 and upper limit=146.06

(b)for n=70, confidence interval=137±t(0.1/2, 69)*34/sqrt(70)=137±1.667*34/sqrt(70)=137±6.77=(130.23,143.77)

lower limit=130.23 and upper limit=143.77

(c)for n=100, confidence interval=137±t(0.1/2, 99)*34/sqrt(100)=137±1.66*34/sqrt(100)=137±5.64=(131.36,142.64)

lower limit=131.36 and upper limit=142.64

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