You are conducting a multinomial hypothesis test ( = 0.05) for the claim that al
ID: 3294093 • Letter: Y
Question
You are conducting a multinomial hypothesis test ( = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category: Observed Frequency: Expected Frequency(?)
A 23
B 24
C 16
D 5
E 17
Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.
What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.) 2=
What are the degrees of freedom for this test? d.f.=
What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value =
The p-value is... less than (or equal to) greater than
This test statistic leads to a decision to...(choose 1)
reject the null
accept the null
fail to reject the null
accept the alternative
As such, the final conclusion is that... (choose1):
There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected.
There is not sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected.
The sample data support the claim that all 5 categories are equally likely to be selected.
There is not sufficient sample evidence to support the claim that all 5 categories are equally likely to be selected.
Explanation / Answer
The statistical software output for this problem is:
Chi-Square goodness-of-fit results:
Observed: Observed
Expected: All cells in equal proportion
Hence,
X2 = 13.529
Df = 4
p - Value = 0.0090
Less than
Reject Null
Option A; There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected.
N DF Chi-Square P-value 85 4 13.529412 0.009Related Questions
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