Question 1: Suppose that the mean and standard deviation of the number of gallon

Question

Question 1:

Suppose that the mean and standard deviation of the number of gallons of milk sold at a local supermarket per day are 2.19.416 and 11.8671, respectively. Fill in the blank: the supermarket will sell greater than __________ gallons of milk on 3.73% of days. Assume the distribution is approximately normal.

A. 240.57

B. 198.26

C. We do not have enough information to calculate the value

D. 31.67

E. 470.50

Question 2:

The average adult femalde is 64.834 inches tall with a standard deviation of 1.5338. Based on this information, 74.79% of adult females are less than what height? Assume the distribution is approximately normal.

A. We do not have enough information to calculate the value

B. 63.81

C. 63.26

D. 65.86

E. 66.41

Explanation / Answer

q1) mean =219.416

standard deviation = 11.8671

z = (x^ -mean)/ std

take from options assume and keep value

z = (240.57-219.46)/11.8671 = 1.778 ~ = 1.78

now from z table we have value as it is greater p(z)>1.78)=1- 0.9625= 0.0375 = 3.75%

option a is nearly equal to answer

2) mean =64.834

standard deviation =1.5338

z = (x^ -mean)/ std

take from options assume and keep value

z=(65.86-64.834)/1.5338 =0.668 ~ =0.67

now from z table we have value as less than p(z)<0.6= 0.7486= 74.86%

option d nearly satifies the above one

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.