Please show work Suppose that a group of researchers is planning to test a new w
ID: 3292831 • Letter: P
Question
Please show work
Explanation / Answer
here std error mean =std deviation/(n)1/2 =1.1/(40)1/2 =0.1739
for 0.01 level critical value of z=2.326
therefore corresponding critical value =z*std error =0.4046
therefore probability that researcher reject their null hypothesis is mean amount is 0.5 lb or more
=P(X>0.4046)=P(Z>(0.4046-0.5)/0.1739)=P(Z>-0.5484)=0.7083 ~ 70.83% =power of the test.
please revert for any clarification required,
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