marginal error=.01662443, porportion of red candy 5 red candy /38 total candy=.1

Question

marginal error=.01662443, porportion of red candy 5 red candy /38 total candy=.132 red candy total number of candy=38 Use that result to construct a 90% confidency interval

C.Construct a confidence interval. ___ < p <. (Round to three decimal places as needed)

D) Write a statement that correctly interprets the confidence interval. Choose the correct answer bellow

a) One has 99% conficence that the interval from the lower bound to the upper boundactually does contain the true value of the population proportion.

b) 99% of sample proportions will fall between the lower bound and the upper bound.

c) there is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.

d) One has 99% confidence that the sample proportion is equal to the population proportion

Explanation / Answer

p=0.132

and n=38

here std error=(p(1-p)/n)1/2 =0.0548

for 90% CI; z-1.645

therefore 90% confidence interval = p -/+ z*std error =0.041 <p<0.222

D)

a) One has 99% conficence that the interval from the lower bound to the upper boundactually does contain the true value of the population proportion.

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