Log in ment-Responses/flast\'dep- 16366330 (b) if measurements are made instead

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Log in ment-Responses/flast'dep- 16366330 (b) if measurements are made instead on 3 separate days and the mean result is compared with the oriterion 140 mgl'd, what is the probability that Shela n dagrosed as atenal diabetes? (Round your answer to four decmal places.) 12. O -/ /t points Mint oStat3 5 E.0r1 Here is a simple probablity model for multiple-choice tests. Suppose t that each student has probability p of correctly answering a question chosen at random from a uverse of possble questions are independent. Jod is a good student for whon p o.Ds CRound your answer to four decimal places.) questions. (A strong student has a higher p than a weak student) The correctness of answers to different questions are ndependent. Od is a (a) use the Normal approximation to find the probabity that lod teres tJod scores 74% or lower on a so-question test. er to for r the test contan s 250 questions, what is the probabty that 30d m. score 74% or lower, use the normal Jeprwubon Read yeur a oron proporton ottaneet to herre vde er·eeee questions must tho test contan questions c) How many questions must the test contain in order to reduce the standard deviation of Jod's order to reduce the standard devate (d) Laura is a weaker student for whom ··0.76. Does the answer you gave n (c) fr standard deviation of Jodi's score apply to unra's stardard deviation also? O yes, the smaller p for Laura has no effect on the relationshp between the number of questions and the standand deviation. O No, the smaller p for Laura alters the relationship between the number of questions and the standard deviation 13 0.561 points 1 Previous Answers inoStats 5.E 00 Type here to search

Explanation / Answer

a)mean = u= 100*0.51=51

standard deviation = sqrt(np(1-p)=sqrt(100.0.51*049)=4.99

now z=(0.74-0.5 1)/4.99=0.0460

p(z<0.046)=0.5160 from standard z table

b) mean =250*0. 51=127.5

standard deviation =sqrt(250*0.51*0.49)=7.90

now z =( 0.74-0.51)/7.9=0.029

p(z<0.029)=0.5080 from standard z table

c)Since std = sqrt(pq/n)

1/2sqrt(pq/n)=sqrt(pq/4n)

4 * 100=400

d) no the smaller p value

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