One-hundred rats whose mothers were exposed to high levels of tobacco smoke duri
ID: 3291389 • Letter: O
Question
One-hundred rats whose mothers were exposed to high levels of tobacco smoke during pregnancy were put through a simple maze. The maze required the rats to make a choice between going left or right at the outset. Eighty of the rats went right when running the maze for the first time. Assume that the 100 rats can be considered an SRS from the population all rats born to mothers exposed to high levels of tobacco smoke during pregnancy. (Note that this assumption may or may not be reasonable, but researchers often assume lab rats are representative of such larger populations because they are often bred to have very uniform characteristics). Let p be the proportion of rats in this population that would go right when running the maze for the first time. A 90% confidence interval for p is 0.8 ± .078. 0.8 ± .040. 0.8 ± .066.
Explanation / Answer
p^ = X/n
here X = 80 , n = 100
for 90 % confidence interval , z = 1.645
margin of error = z* sqrt(p^q^/n)
= 1.645 *sqrt(0.8*0.2/100)
= 0.0658 = 0.066
hence confidence interval is
(0.8 ± .066)
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