In the book Advanced Managerial Accounting, Robert P. Magee discusses monitoring
ID: 3291061 • Letter: I
Question
In the book Advanced Managerial Accounting, Robert P. Magee discusses monitoring cost variances. A cost variance is the difference between a budgeted cost and an actual cost. Magee describes the following situation: Michael Bitner has responsibility for control of two manufacturing processes. Every week he receives a cost variance report for each of the two processes, broken down by labor costs, materials costs, and so on. One of the two processes, which we'll call process A , involves a stable, easily controlled production process with a little fluctuation in variances. Process B involves more random events: the equipment is more sensitive and prone to breakdown, the raw material prices fluctuate more, and so on. "It seems like I'm spending more of my time with process B than with process A," says Michael Bitner. "Yet I know that the probability of an inefficiency developing and the expected costs of inefficiencies are the same for the two processes. It's just the magnitude of random fluctuations that differs between the two, as you can see in the information below." "At present, I investigate variances if they exceed $2,822, regardless of whether it was process A or B. I suspect that such a policy is not the most efficient. I should probably set a higher limit for process B." The means and standard deviations of the cost variances of processes A and B, when these processes are in control, are as follows: (Round your z value to 2 decimal places and final answers to 4 decimal places.): Process A Process B Mean cost variance (in control) $ 4 $ 2 Standard deviation of cost variance (in control) $4,685 $9,531 Furthermore, the means and standard deviations of the cost variances of processes A and B, when these processes are out of control, are as follows: Process A Process B Mean cost variance (out of control) $6,604 $ 6,223 Standard deviation of cost variance (out of control) $4,685 $9,531 (a) Recall that the current policy is to investigate a cost variance if it exceeds $2,822 for either process. Assume that cost variances are normally distributed and that both Process A and Process B cost variances are in control. Find the probability that a cost variance for Process A will be investigated. Find the probability that a cost variance for Process B will be investigated. Which in-control process will be investigated more often. Process A Process B is investigated more often (b) Assume that cost variances are normally distributed and that both Process A and Process B cost variances are out of control. Find the probability that a cost variance for Process A will be investigated. Find the probability that a cost variance for Process B will be investigated. Which out-of-control process will be investigated more often. Process A Process B is investigated more often. (c) If both Processes A and B are almost always in control, which process will be investigated more often. will be investigated more often. (d) Suppose that we wish to reduce the probability that Process B will be investigated (when it is in control) to .2743. What cost variance investigation policy should be used? That is, how large a cost variance should trigger an investigation? Using this new policy, what is the probability that an out-of-control cost variance for Process B will be investigated? k P(x > 5,721) rev: 10_17_2016_QC_CS-66206, 03_15_2017_QC_CS-82862
Explanation / Answer
According to the given question,
(A)Assuming that cost variances are normally distributed and that both Process A and Process B cost variances are in control.
P(a cost variance for Process A will be investigated) =P(X>2822)
Standardising the above we have P(Z>(2822-4)/4685) = P(Z>0.60149) =0.2743
P(a cost variance for Process B will be investigated) =P(Y>2822)
Standardising the above we have P(Z>(2822-2)/9531) = P(Z>0.30) =0.3821
Since, the probability of Process B being investigtaed is more we can say that for IN CONTROL processes Process B will be investigated more often.
(B)Now,assuming that cost variances are normally distributed and that both Process A and Process B cost variances are out of control
P(a cost variance for Process A will be investigated) =P(X>2822)
Standardising the above we have P(Z>(2822-6604)/4685) = P(Z>-0.80725) =0.791
P(a cost variance for Process B will be investigated) =P(Y>2822)
Standardising the above we have P(Z>(2822-6223)/9531) = P(Z>-0.36) =0.6406
Since,the probability of Process A being investigated is more we can say that for OUT OF CONTROL processes Process A will be investigated more often.
(C)If both the processes A and B are almost always in control then Process B will be invetigated more often.
(D) Now we want P(a cost variance for Process B will be investigated)=0.2743
P(Y>C)=0.2743 *C is the cost variance used in the policy
Standardising we have P(Z>(C-2)/9531)=0.2743
Comparing with standard normal values we get (C-2)/9531 = 0.60
So, we have C =5720.6 ~5721
Thus, we conclude that a cost variance of 5721 or moe should trigger an investigation.
Now, for the out of control process in case of process B the probability of being investigated is
P(Y>5721) =P(Z>(5721-6223)/9531)
P(Z>-0.05)= 0.5199
Process A Process A Process B Process B Mean Standard Deviation Mean Standard Deviation In Control $4 $4685 $2 $9531 Out of Control $6604 $4685 $6223 $9531Related Questions
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