1. A college plans to interview 8 students for possible offer of graduate assist

Question

1. A college plans to interview 8 students for possible offer of graduate assistantships. The college has three assistantships available. How many groups of two can be selected?
If the college has two assistanships available how many groups of three can be selected?
56? 1. A college plans to interview 8 students for possible offer of graduate assistantships. The college has three assistantships available. How many groups of two can be selected?
If the college has two assistanships available how many groups of three can be selected?
56?
If the college has two assistanships available how many groups of three can be selected?
56?

Explanation / Answer

It is a permutation-combination problem, since we have to select 8 out of 3 .

So, 8C3 ways to do this.

Now, 8C3 = 8!/(8-3)!*3! = 8!/5!*3! = 1*2*3*4*5*6*7*8 / (1*2*3*4*5)(1*2*3)

= 6*7*8 / 1*2*3

=7*8

= 56

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