The figure shows a circuit containing an electromotive force, a capacitor with a

Question

The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (Ohm). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoffs Law gives RI = Q/C, E(t) But I = dQ/dt, so we have Suppose the resistance is 5 Ohm, the capacitance is 0.04 F, and E(t) = 50sin(30t) V, and the initial charge is Q = 0 C. Find the charge at time t. Q(t) = Find the current at time t. I(t) =

Explanation / Answer

q(t) = Q( 1 - e^(-t)) where t = RC.... i hopw you can put values.... and Q = CV total charge possible

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