Homework: practice problems- module 4 Score: 0 of 1 pt 3.3.43 Save | 5 of 5 (1 c
ID: 3283563 • Letter: H
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Homework: practice problems- module 4 Score: 0 of 1 pt 3.3.43 Save | 5 of 5 (1 complete) ? HW Score: 20%, 1 of 5 pts Question Help * Heights of women have a bell-shaped distribution with a mean of 162 cm and a standard deviation of 7 cm. Using Chebyshevs theorem, what do we know about the percentage of women with heights that are within 3 standard deviations of the mean? What are the minimum and maximum heights that are within 3 standard deviations of the mean? At least L1% of women have heights within 3 standard deviations of 162 cm. Round to the nearest percent as needed.)Explanation / Answer
Chebyshev's formula: = P = 1 - 1/k², where k = number of standard deviations
P = 1 - 1/3² = 1 - 1/9 = 8/9 or 88.9%
At least 88.9% of women have heights with 3 standard deviations of 162 cm.
Minimum height =162 - (3)(7) = 141 cm
Maximum height= 162 + (3)(7) = 183 cm
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