Please post the steps of solution the event wonty that an event happens is 0.42.

Question

Please post the steps of solution
the event wonty that an event happens is 0.42. What is the probability that the event won't happen? a) 0.58 b) -0.42 c) 0 d) 1 Q-7: If the probability that tomorrow will not be clear is 0.4 then the probability that tomorrow will be clear is: a) 0.6 b) 0.2 c) 0.8 d) 0.42 e) None of the above Q-8: A coin is flipped and a die is rolled. The probability of getting a head and a 4 is a) 1/8 b) 1/4 c) 3/8 d) 1/12 Q-9: A couple has three children. The probability that the couple has exactly two boys or two girls is f) 1/8 g) 1/2 h) 3/4 i) 3/8 i) None of the above Q-10: A pair of fair dice are rolled once with outcomes x and y. The probability of getting 7 or 11 is f 1/6 g) 2/9 h) 1/18 i) I/12 j) None of the above Q-11: A pair of fair dice are tossed once, and the product of the two faces outcome numbers, x and y, is recorded. The probability of the event, fx.y-49) is k) 1

Explanation / Answer

6. Probability of event won't happen = 1 - Probability of event happen = 1 - 0.48 = 0.52 (a)

7. Probability of event happen = 1 - Probability of event won't happen = 1 - 0.4 = 0.6 (a)

8. Probability of getting head from coin = 1/2

Probability of getting 4 from dice = 1/6

So the Probability of getting head and 4 = 1/2 * 1/6 = 1/12 (d)

9. There are total 4 ways to have 3 children

Boy, Boy, Boy

Girl, Girl, Girl

Boy, Boy, Girl

Boy, Girl, Girl

out of these 4 we require 2 set (B, B, G & B,G, G)

So probability = 2/4 = 1/2 (g)

10. So there are total 36 combination from 2 dice like (1,1) (1,2) .. ..(2,1) (2,2) ...(6,6)

out of these we reqire for 7 = (1,6 ) (2,5) (3,4) (4,3) (5,2) (6,1) total 6 set

and for 11 = (5,6) (6,5) total 2 set

So Probabilty of getting 7 and 11 = (6+2) / 36 = 8 / 36 = 2 / 9 (g)

11. out of 36 combination there is not set that give 49 because we have most larger number in dice is = 6

so 6*6 = 36 not equal to 49

SO  Probability = 0.

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