compatibilité]- PowerPoint (Echec de l\'activation du produit) AMA REVISION AFFI

Question

compatibilité]- PowerPoint (Echec de l'activation du produit) AMA REVISION AFFICHAGE Remplissage Rech { } |-| Organiser Styles 13 niis jerganiser Styles Contour , ac Remi Sélec GI Modif Effets . rapides , aragraphe Dessin 5-13 SAMPLE PROBLEM 5.12 : MA-40N·m, f,:0.3 , ; :Mc. The mechanism consist of two levers and a slide. All the weights of the body system can be neglected. A moment MA-40N.m is applied on the lever AD. The friction factor between the slide and the lever AD isf-0.3. Determine the moment Mc applied on the lever CB when the mechanism is in equilibrium. ter des commentaires : COMMENTARES ,I COMMENTAIRES

Explanation / Answer

Since there won't be any for e which can Apply here any torque

Like all the normal forces will be passing through axis 'ac' so it will not give any torque.

So only torque present is 'Ma' and that has to be balanced by 'Mc'

So Mc=40 Nm

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