2)(15 points) A silver wire has a cross sectional area A =1.04 mm2. Atotal of 9.

Question

2)(15 points) A silver wire has a cross sectional area A =1.04 mm2. Atotal of 9.4×1018 electrons pass through the wire in 3.0s. The conduction electron density in silver is 58 × 1028 electrons/m3 and e = 160-10-190. what is the drift velocity of these electrons? A) 5.2 10-5 m/s B)9.1 10-5 m/s C)27-10-5 m/s D) 1.1-10-5 m/s E)74-10-5m/s 3) (15 points) You need to design a 1.0 A fuse that "blows" if the current exceeds 1.0 A. The fuse material in your stockroom mealts at a current density of 500 A/cm2. The diameter of the wire of this material that will do the job is A) 0.1 mm B) 0.2 mm C) 0.3 mm D) 0.4 mmm E) 0.5 mm 2A

Explanation / Answer

2) A = 1.04 mm2 = 1.04 * 10-6 m2

current I = n e / t

= 9.4 * 1018 * 1.6 * 10-19 / 3

= 0.501 A

drift velocity = I / n e A

= (0.501) / (5.8 * 1028 * 1.6 * 10-19 * 1.04 * 10-6)

drift velovity = 5.2 * 10-5 m/s

[option A]

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