Problem 25.23 - Enhanced - with Feedback Part A A 2.9-cm-diameter parallel-plate

Question

Problem 25.23 - Enhanced - with Feedback Part A A 2.9-cm-diameter parallel-plate capacitor has a 1.7 mm spacing. The electric field strength inside the capacitor is 1.3x10 V/m What is the potential difference across the capacitor? Express your answer to two significant figures and include the appropriate units. You may want to review pages 699- 702) VO= 1 Value Units Submit My Answers Give Up Part B Express your answer to two significant figures and include the appropriate units Q= | Palue Units Submit My Answers Give Up

Explanation / Answer

here,

radius , r = 2.9/2 cm = 0.0145 m

spacing , d = 1.7 mm = 1.7 * 10^-3 m

electric feild , E = 1.3 * 10^5 V/m

a)

the potential difference , V = E * d

V = 1.3 * 10^5 * 1.7 * 10^-3 V

V = 221 V

b)

the charge on each plate , Q = C * V

Q = area * e0 /d * E * d

Q = pi * ( 1.7 * 10^-3)^2 * 8.85 * 10^-12 * 1.3 * 10^5 C

Q = 1.04 * 10^-11 C

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