Use the Fletcher-Munson curves of equal loudness to answer the following questio
ID: 3281109 • Letter: U
Question
Use the Fletcher-Munson curves of equal loudness to answer the following questions. Remember that the horizontal axis is marked as a logarithmic scale. The divisions between 100 and the far left represent 90, 80, 70, 60, 50, 40, 30, and 20. The divisions between 100 and 1000 represent 200, 300, 400, 500, 600, 700, 800, and 900 Equal loudness in phons 20 120 100 60 2 40 30 20 100 10,000 1000 Frequency (Hz) What is the minimum threshold of hearing in intensity level (decibels) for a tone at 9000 Hz? (Do not enter units) Submit Answer Tries 3/10 Previous Tries of a 65 db tone at 9000 Hz? (Enter the answer in phons. Do not enter units.) Submit Answer Tries 1/10 Previous Tries What is the intensity level required for a 200 Hz tone to have a loudness of 50 phons? Submit Answer Tries 0/10Explanation / Answer
1)
The 9000 Hz frequency corresponds to the vertical line next (on the left) to the 10000Hz bold vertical line. The lowest bold line is the minimum threshold of hearing for any frequency. The intersection of dashed curve and the 9000Hz vertical line is our answer to this question. This intersection point lies just above the 20 decible point (approximately 20 decible). Find the exact value from your graph coordinates and input in the blank or if the resolution is not more than what is shown in the image then input the value 20.
2)
We have 9000 Hz in frequncy and 65 decibles. The intersection point of these two has a loudness curve given which corresponds to the 60 phons loudness curve. The answer is 60 to be put in the blank.
3)
For 200 Hz, the 50 phon loudness curve intersects it at 50 decible intensity. Hence the answer is 50 to be input in the blank.
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