(40 points) 50 kg/s of light oil, with a specific heat of 1.8 kJ/kgK, is to be h
ID: 3280932 • Letter: #
Question
(40 points) 50 kg/s of light oil, with a specific heat of 1.8 kJ/kgK, is to be heated using the condensation of steam at 100°C (going from saturated vapor to saturated liquid) in a cross flow heat exchanger where the fluids do not mix. The light oil is heated from 25°C to 50°C in the oil-side of the exchanger. The overall heat exchanger has negligible heat transfer, meaning the heat transfer rate of the oil and the steam offset. Determine: (a) the mass flow rate of the steam, (b) the heat transfer rate of the oil, and (c) the heat transfer rate of the steam (aExplanation / Answer
(b) heat transfer rate to oil= flow rate of oil * speific heat *increase in temperature =50 *1.8 *103*25=2.25MJ/s
(c)heat transfer rate from steam=heat transer rate to oil =2.25MJ/s
(a)mass flow rate of steam = heat transfer rate/(latent heat of vaporization of water)=2.25*106/2.26 * 106 =0.995Kg/s
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.