1. Find the electric field amplitude of a linearly-polarized visible light em wa

Question

1. Find the electric field amplitude of a linearly-polarized visible light em wave of intensity 555 MW/m2 moving at a speed of 1 .240 × 108 m/s through diamond (a nonmagnetic dielectric). (Remember to replace the metric prefixes with their powers of 10 when needed in problems on all drill sets.) EQUATION USED (ONE SIGN) Remember to replace the merie prefixes with powers of 10 when needed in problems on all drill sets.) SOLUTION ANSWER Calculate the dielectric constant of diamond for the light of Problem I above. EQUATION USED (ONE SIGN) SOLUTION ANSWER 3. A linearly-polarized em wave moving in vacuum dicular to a perfectly absorbing surface exerts a radiation of 678 Pa on that surface. Find the intensity of that em wave SOLUTION ANSWER EQUATION USED (ONE SIGN) 4. At one position and time, the electric field of an em wave in vacuum is 12.12 M/m into the paper () and its magnetic field is 40.4 mT left (-). Find the corresponding Poyating vector (direction relative to the paper). VECTOR EQUATION USED SOLUTION in calculating the magnitude. ANSWER Here I use MAGNITUDE DIRECTION 3.You are traveling north at 22 m/s in your convertible. You have just (Thus, you are moving apart at 37 m/s.) The speed of sound is 342 m/s. The truck is blasting a horn that you hear to be at 88 Hz. Find the frequency that the truck driver hears from her horn. (You should complete the sketch, writing L in one O and S in the other O. Then draw an arrow showing the itive (+) direction. Finally, add two arrows (with signed numbers) showing the L and S velocity components.) LUTION ANSWER The truck driver has no speed relative to her horn, so she hears/. (Fill in the subscript.) you - truck

Explanation / Answer

Solving 1st question

Q1

Electric field is given by

I=0.5*c*n*epsilon*E*E

So E=sqrt(2I/c*n*epsilon)

E=415605.5 N/C

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