in the third part how is surface area of a pipe is pi*d*L . shouldn\'t it be are

Question

in the third part how is surface area of a pipe is pi*d*L . shouldn't it be area of a cylinder 2*pi*r(r+L) plz explain this point

PROPERTIES OF FLUIDS relationi where= velocity of nuid at a distance y from solid boundary. Calculate i) Shear stress at the wall (ii) Shear stress at 1 em from the all (iii) Total resistance for a 2.5 em dia pipe over a length of 80 m. Take 0.4 poise. Solution : Given H0.4 poise 0.04 NS/m2 d=2.5 cm e 0.025 m, 1 = 80 m . Velocity gradient, dy (4) At the wall surface. Shear s dy = 0.04 x 3-o 12 N/m2 trees, t du dy (ii) At Shear stress, = 0.04 x 1 0.04 N/m, Shear force Surface area of pipe (iii) Shear stress,

Explanation / Answer

Ans: While fluid flowing inside a pipe due to the walls of the pipe the fluid will face shear force..

And the surface area of the pipe is 2*pi*inner radius of pipe*length of pipe=2*pi*r*l=pi*2r*l=pi*d*l

Here d is the diameter of the pipe.

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