(12%) Problem 3: An electron (m-9.109 x 1031 kg) is in the presence of a constan

Question

(12%) Problem 3: An electron (m-9.109 x 1031 kg) is in the presence of a constant electric field E. The electron has a charge of e = 1.602 × 10-19 C and it accelerates at a rate ofa-6900 m/s 33% Part (a) write an expression for the magnitude of the electric field. Grade Surn E= Potential Submissios Attempts re (0% per att detailed vi 1 2 3 SubenitHint I give upt Hints: 0% deduction per hint. Hints remaining 2 Feedback: 0n deduction per feedback 33% Part (b) what is the field, in units of NC? 33% Part (c) Assuming the electron begins at rest, what is its velocity after 2.5 s? Give your answer in meters per second.

Explanation / Answer

a)
Consider F be the force on the electron.
F = ma      ...(1)
where m is the mass and a is the acceleration of the electron.
F = eE      ...(2)
e is the charge of electron and E is the electric field.

Combining (1) and (2),
E = ma/e

b)
E = ma/e
m = 9.109 x 10-3 kg
a = 6.9 x 103 m/s2.
e = 1.602 x 10-19 C
Substituting the values,
E = [(9.109 x 10-31) x (6.9 x 103)] / (1.602 x 10-19)
= 3.923 x 10-8 N/C

c)
Initial velocity, u = 0
Acceleration, a = 6.9 x 103 m/s2.
Time taken, t = 2.5 s
Consider v be the final velocity.
Using the formula, v = u + at,
v = 0 + (6.9 x 103) x 2.5
= 1.725 x 104 m/s

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