In case E, a positive point charge with +0 is a distance s away from a second po

ID: 3279047 • Letter: I

Question

In case E, a positive point charge with +0 is a distance s away from a second positive point charge +q. In case F ten positive point charges, each with charge +Q/10, lie along an arc of radius s centered on a positive point charge +. c. +010 Is the net electric force on the +q charge in case E greater than, less than, or equal teo the net electric force on the +q charge in case F? Explain. Case F 4. A thin semicircular rod has a total charge +Q uniformly distributed along it. A negative point charge-Q is placed as shown. A test charge +q is placed at point C. (Point C is equidistant from-0 and from all points on the rod.) -0 Let Fe and F represent the force on the test charge due to the point charge and the rod respectively. Is the magnitude of Fe greater than, less than, or equal to the magnitude of F? Explain how you can tell a. b. Is the magnitude of the net force on +q greater than, less than, or equal to the magnitude of Explain. c. A second negative point charge-0 is placed as shown. Is the magnitude of the net electric force on +q greater than, less than, or equal to the magnitude of the net electric force on +g in part b? Explain. -0 -0 CPearson Custom Publishing

Explanation / Answer

Problem 4)

a) The magnitude of the force on the test charge by the point charge (FP) greater than the magnitude of the force on the test charge by the rod (FR), because the y-components of segments of the rod cancelling out each other.

b) The charge at point C is positive, so it is being attracted to the negative point charge. It is also being repelled from the positively charged rod, so FP and FR are in the same direction, and probably add, given the symmetry of the configuration. If they add, the net force is greater than FP, since it includes FP.

c) Now second charge -Q will attract the +q charge, that force will be in opposite direction than the direction in part (b). So, the net force on +q will be lesser than force in part (b).

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In case E, a positive point charge with +0 is a distance s away from a second po

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