e-HW-2Problem 2.93 « previous | 10 of 22 next » Part A Problem 2.93 f FB 740 N,

Question

e-HW-2Problem 2.93 « previous | 10 of 22 next » Part A Problem 2.93 f FB 740 N, and Fo 580 N, determine the magnitude of the resultant force acting on the flag pole. (Figure 1) Express your answer to three significant figures and include the appropriate units. FR : 1 Value Units Submit My Answers Give Up Part B Determine the coordinate direction angle a of the resultant force acting on the flag pole. Express your answer to three significant figures and include the appropriate units. Figure 1 of 1 Value Units Submit My Answers Give Up 6 m Part C Determine the coordinate direction angle of the resultant force acting on the flag pole. Express your answer to three significant figures and include the appropriate units. 2 m Value Units Submit My Answers Give Up

Explanation / Answer

partA] Resultant force = [740*2/sqrt(2^2+3^2+6^2) + 580*3/sqrt(2^2+3^2+6^2)] i

+  [740*-3/sqrt(2^2+3^2+6^2) + 580*2/sqrt(2^2+3^2+6^2)] j

+  [740*-6/sqrt(2^2+3^2+6^2) + 580*-6/sqrt(2^2+3^2+6^2)] k

= 460 i -151.4 j -1131.4 k

magnitude of resultant force = sqrt(460^2+151.4^2+1131.4^2)

= 1.23*10^3 N

partB] alpha = arccos(460/1230) = 68.0 degree

partC] beta = arccos (-151.4/1230) = 97.1 degree

partD] gamma = arccos(-1131.4/1230) = 157 degree

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