One of the three types of motion you explored was constant velocity, but was the
ID: 3278931 • Letter: O
Question
One of the three types of motion you explored was constant velocity, but was the velocity of the cart totally constant during your trials or did it slow slightly? What are some factors that may have caused the velocity of the cart not to be constant? Another type of motion you explored was constant acceleration. What caused the constant ration of the cart? How could you have increased this acceleration, and how would your graphs of position and velocity versus time be different if the acceleration was greater? Imagine you were standing in front of a motion sensor which was measuring your position as a function of time as you moved toward or away from the sensor. Assuming the graph below s data, describe your motion during data collection in terms of your speed and direction.Explanation / Answer
1. IN the motion of the cart, the velocity of the cart slowly decreased. This was becuase of the friction force of the air and the track, that cannot be avpoided in practical situations and hence effects the motion of the cart.
2. the constant acceleration of the cart was caused when the cart was let go off from an inclined plane.
the acceleration of the cart would have increased by increasing the angle of the plank with respect to the horizontal
if acceleratio was greater, position vs time graph will have higher values of the slopes
velocity vs time greaph will have higher value of the slope and higher magnitude
the acceleration vs time graph will have higher magnitude of constant acceleration
3. the position vs time graph is given
here we can see, in first 2 seconds, the position is constant, acceleration is 0, velocity of man is 0
for the next 3 seconds, distance from sensor has increased with constant slope, so the person is moving away from the sensor at constant velocity, 0.75/3 = 0.25 m/s
for the next 1 second, the man is statioary again
for the next 2 seconds, the man is moving towards the sensor with a speed of 0.5/2 = 0.25 m/s
for the next two seconds the man ius stationary
for the 3 seconds the man is moving away from the sensor at a speed = 0.75/3 = 0.25 m/s
for the last 2 seconds he is statioonary again
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