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You are in a rocket ship, in outer space. You have a nuclear reactor that suppli

ID: 3278676 • Letter: Y

Question

You are in a rocket ship, in outer space. You have a nuclear reactor that supplies a constant power , P0, and a large supply of iron pellets. The Iron pellets comprise 99/100 of your ship's mass, m. You can use the power to eject the tiny iron beads out the back of your ship with an electromagnetic "gun". You can control the rate at which you fire them and their velocity, but are limited by your power plant. (you can't fire an arbitrarily large mass at an arbitrarily large velocity.) As you fire off the beads, your ship moves in the opposite direction to conserve momentum ]. In addition, the mass of your ship decreases.

(d) what is your final velocity in part (c)? how does it compare to the answer in part (b)?

Note: I have solved (a) and (b) I am just looking for the solutions to (c) and (d) I provided the whole question just to give context

Explanation / Answer

c) for optimal firing rate, let the rate be r = dm/dt

at time t

mass left of rocket = (m - rt)

so from momentum conservation

(m - rt)du = (sqroot(2*Po*dt*dm))

(m - rt)du = (sqroot(2*Po*r))dt

du/(sqroot(2*Po*r)) = dt/(m - rt)

integrating from u = 0 to u = u

t = 0 to t = t

u/(sqroot(2*Po*r)) = ln[(m)/(m - rt)]/r

u = -sqroot(2*PO*r)*ln(1 - rt/m)/r

du/dt = sqroot(2*Po*r)/m*(1 - rt/m) = 0 for maximum u

rt/m = 1

r = m/t for maximum velocity

hence

u = -sqroot(2*PO*r)*ln(1 - rt/m)/r

d) Final velocity in part c is greater than that of part b

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