At a factory that produces pistons for cars Machine 1 produced 168 satisfactory

Question

At a factory that produces pistons for cars Machine 1 produced 168 satisfactory pistons and 42 unsatisfactory pistons today Machine 2 produced 180 satisfactory pistons and 120 unsatisfactory pistons today. Suppose that one piston from Machine 1 and one piston from Machine 2 are chosen at random from today's batch. What is the probability that the piston chosen from Machine 1 is unsatisfactory and the piston chosen from Machine 2 is satisfactory? Do not round your answer. (If necessary consult a list of formulas.)

Explanation / Answer

Number of statisfactory pistons from Machine 1 = 168

Number of unsatisfactory pistons from Machine 1 = 42

Total number of pistons from Machine 1 = 168 + 42 = 210

=> Probability that a piston from Machine 1 is unsatisfactory = 42 / 210 = 0.2

Number of statisfactory pistons from Machine 2 = 180

Number of unsatisfactory pistons from Machine 2 = 120

Total number of pistons from Machine 2 = 180 + 120 = 300

=> Probability that a piston from Machine 2 is satisfactory = 120 / 300 = 0.4

Therefore, probability that the piston chosen from Machine 1 is satisfactory and the pistonn chosen from Machine 2 is unsatisfactory = 0.2 * 0.4 = 0.08.

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